- When Quantity
*A*is inversely proportional to Quantity*B*, it means that:- the line graph between Quantity
*A*and Quantity*B*is an exponential. - the line graph between Quantity
*A*and Quantity*B*is a straight line, but does not go through the origin. - the line graph between Quantity
*A*and 1/Quantity*B*is a straight line. - the line graph between Quantity
*A*and 1/Quantity*B*is a straight line with a positive gradient that passes through the origin.

- the line graph between Quantity
- You are asked to find the gradient of a curved graph at a certain point. Which one of these is the correct way to do this?
- Read the
*y-*value at that point and divide it by the*x*-value - Read the maximum
*y*-value and divide it by the maximum*x*-value - Draw a tangent. Ensure that the straight line is as long as possible and then divide the rise by the run.
- Draw a tangent. Ensure that the straight line is as long as possible and then divide the run by the rise.

- Read the
- When you work out the gradient of a tangent, which one of these is the correct statement about the gradient?
- It gives the instantaneous value of rate of change at that point.
- It gives an average value of rate of change at that point.
- A rate of change can only be worked out if the gradient is increasing.
- No useful information can be gained from the gradient.

- When finding the area under a graph that shows direct proportionality, which one of these statements is correct?
- The area for a particular value can be worked out by
*x*-value ×*y*-value. The units are units for*x*× units for*y*. - The area for a particular value can be worked out by
*x*-value ×*y*-value. The units are units for*x*÷ units for*y*. - The area for a particular value can be worked out by 1/2 ×
*x-*value ×*y*-value. The units are units for*x*× units for*y*. - he area for a particular value can be worked out by 1/2 ×
*x*-value ×*y*-value. The units are units for*x*÷ units for*y*.

- The area for a particular value can be worked out by
- When working out the area under a curved graph, which one of these is the correct statement? The graph is plotted on normal graph paper.
- It is easiest to count the squares under the graph. All squares are counted. It is important that the scales are taken into account.
- It is easiest to count the squares under the graph. If more than half the square is under the graph, it's counted. If less than half the square is under the graph it's ignored. It is important that the scales are taken into account.
- It is easiest to count the squares under the graph. Only whole squares are counted. It is important that the scales are taken into account.
- Counting squares is considered to be rather unscientific and error prone.

- This graph shows a car travelling along a straight and level road. It accelerates to a constant higher speed. Which one of the the following would give the distance travelled while the car was accelerating>
- Triangle Q;
- Rectangles P, R, and S;
- Triangle Q and Rectangle R
- Triangle Q and Rectangles P, R, and S

- When plotting a graph with error bars, which one of these is the correct way to use them?
- Error bars should be there for both x and y axes. They should use the percentage uncertainty.
- Error bars should be there for both x and y axes. They should use the absolute uncertainty.
- Error bars should be there for the y axis only. They should use the percentage uncertainty.
- Error bars should be there for the y axis only. They should use the absolute uncertainty.

- When considering uncertainty in a graph that goes through the origin, which one statement is true for the origin?
- The origin has no uncertainty.
- The origin is treated as having the same percentage uncertainty as the lowest value.
- The origin is treated as having the same absolute uncertainty as the lowest value.
- The origin is treated as having the same percentage uncertainty as the highest value.

- Your physics tutor tells you to draw lines of worst fit as well as a line of best fit. What should you do?
- You join the points dot to dot.
- Your data do not fit into the expected pattern, so you draw any straight line
- You draw the line of worst fit so that it passes through error bars with a gradient slightly above (or below) the line of best fit.
- You need to force the line through the origin, even though the line of best fit does not pass through the origin.

- It is possible to work out the uncertainty of a data set using the gradients from the graph. How would you do this?
- Take the maximum difference of the data points from the line of best fit. Then you take the minimum difference. You then average them, and divide by the average of all the data.
- You work out the gradient of the line of best fit and the gradient of the line of worst fit. You find the difference. Then you divide the difference by the gradient of the line of best fit and convert it into a percentage.
- You work out the gradient of the line of best fit and the gradient of the line of worst fit. You find the difference. Then you divide the difference by the gradient of the line of worst fit and convert it into a percentage.
- You wouldn't. It is highly unscientific and is frowned upon.