Answer to Question 7

Back

 

(a) w = 2pf = 2 p 3.0 Hz = 18.85 rad s-1

 

(b) x = 0.080 m cos (18.85 rad s-1 2.3 s) = -0.0648 m (i.e. below the rest position) = 0.065 m

 

(c) v = -0.080 m 18.85 rad s-1 sin (18.85 rad s-1 2.3 s) = 0.885 m s-1 = 0.89 m s-1

 

(d) a = -0.080 m (18.85 rad s-1)2 cos (18.85 rad s-1 2.3 s) = 23.0 m s-2

 

2 significant figures as the data are to 2 s.f.