Magnetic Fields Tutorial 1 - Magnetic Fields
You will be familiar with the basic notion of a magnetic field, in which magnetic materials experience a magnetic force. The force can come from an electric current, or a piece of magnetised material like a permanent magnet. Magnetic fields are different to other force fields because they are formed by dipoles (i.e. all magnets have a North and a South pole).
Electric fields are made using a single positive or negative point charge, and gravity is caused by point masses. You never get a magnetic monopoles. If you break up a magnet, you still get north and south poles:
This happens even if you grind the magnet down to atom sized particles.
It is worth revising some of the basic ideas that you will have come across in early secondary school.
Magnetic
fields can be shown by field lines, which go from North to South.
The field lines in a strong magnetic field are more closely packed than in a weak field.
Unmagnetised
materials are attracted to either pole.
Like
poles repel; unlike poles attract.
In the Earth’s magnetic field, the North pole will align itself to point to the North, if the magnet is allowed to swing freely.
The Earth has a magnetic field like a bar magnet. Notice that the S-pole is under the North geographic pole. Be careful not to be confused by this.
We
never get single magnetic poles; if there is an N-pole, there must also be
an S-pole to go with it.
Only
iron, cobalt, and nickel and their alloys are magnetic.
Note that these elements are next to each other in the periodic table. They are transition elements.
We can show the fields of two magnets attracting:
And repelling:
There is a neutral point where there is zero force.
Domain Theory of Magnetism
Magnets are
thought to result from the action of tiny atomic magnets called
domains. This can be explained by the
movement of electrons that represent a tiny electric current that results in
magnetism. In most materials, the currents cancel out.
If some of the domains are lined up, then the material is partially magnetised.
If
the domains are fully lined up, the magnet
is saturated, and cannot be magnetised
further.
Some
materials like soft iron lose their
magnetism quickly. These are used for temporary
magnets. Permanent or
hard
magnetic materials do not lose their magnetism.
Magnetic effect of an electric current
Electric currents are always associated with magnetic fields. The domains in a magnet are caused by the movement of electrons in shells. Electric currents always produce a magnetic field, even if the wire itself is not made of a magnetic material. The magnetic field of a single current carrying wire is like this:
The
direction of the current is determined by the Screwdriver
Rule.
The magnetic field strength depends on two factors:
the current;
the distance from the wire.
The relationship is:
Note that the magnetic field strength varies inversely with the distance, while gravity and electric fields vary inversely with distance^{2}.
Magnetic fields will interact. In the picture below two current carrying wires with the currents flowing in the same direction.
There is a neutral point between the two wires where the magnetic field cancels:
The two wires attract.
If the currents are in the opposite direction, there is repulsion:
Notice that there is a resultant magnetic field.
This brings us onto a very important property of magnetic fields. Magnetic field strength or flux density is a vector quantity. The direction is important. Note also that magnetic fields are three-dimensional, although we show them as two dimensional as it's easier to do this. (I am not a very good artist.)
Magnetic field of a Solenoid
A solenoid is a coil of wire usually wrapped around a former.
The magnetic field of a solenoid is like a bar magnet.
The diagrams show a three dimensional picture in two dimensions. We can show the directions of the current more easily using dot and cross diagrams:
The current is shown vertical to the page (or screen - let's get up to date!). Outside the solenoid, the magnetic field is like this.
If the current goes clockwise, we get a south pole. If the current goes anti-clockwise, it's a north pole.
The Magnetic Field Strength of an Electric Current (Welsh Board and Eduqas)
Consider a solenoid of n turns per metre which is carrying a current of I amps.
Note that the term n is turns per metre. So you need to divide the total number of turns by the length.
If we measure the flux density in the solenoid well away from the ends, we find that:
B µ I
and
B µ n
So we can write:
B µ nI
There is a constant of proportionality which is called the permeability of free space. It given the physics code m_{0} ("mu-nought" - the symbol 'm' is 'mu', a Greek lower case letter 'm'). The units for the permeability of free space are Henry per metre (H m^{-1})
m_{0} = 4p × 10^{-7} H m^{-1} = 1.257 × 10^{-6} H m^{-1}
Do not mix up the permeability of free space m_{0} with the permittivity of free space e_{0}. The two words sound similar.
Strictly speaking, the permeability of free space applies to a vacuum. However the value in air is very similar.
In some calculators, keying in "4p ×10(-)7" gives a syntax error. Key in "4p × 1 ×10(-)7" or "4 ×10(-)7 × p and it will work. |
We can write an equation for this:
B = m_{0}nI
Worked Example A solenoid of length 2.5 cm has 200 turns. A current of 1.65 A flows through it. Calculate the resulting magnetic field strength. Give your answer to an appropriate number of significant figures. |
Answer
The number of turns per metre = 200 turns ÷ 0.025 = 8000 turns per
metre. |
If we slide a bar of magnetic material into the central space of the solenoid, we have added a core. The magnetic field strength is increased by a factor m_{r} ("mu-arr"), which is called the relative permeability. This factor is a ratio; therefore there are no units. Our equation becomes:
B = m_{0 }m_{r}nI
The relative permeability of pure iron is about 5000. Non-magnetic materials have a relative permeability of 1.
Force on a Current Carrying Wire
You will be familiar with the motor effect. If we put a current carrying wire in a magnetic field, we see that there is a force. The picture below shows a typical demonstration:
A carbon rod is placed in the magnetic field of a large permanent magnet. (You can't get anything less magnetic than carbon!) The brass rails connect the carbon rod to the power supply. When a current flows through the carbon rod in the directions indicated by the arrows, the rod experiences a force and moves from left to right. This shows that the current in the carbon rod makes a magnetic field that interacts with the magnetic field from the permanent magnet to produce a force.
If we turn the magnetic field so that it is parallel to the rails, the force is zero.
We
can work out the force that is exerted on the wire quite simply.
Experiment shows us that the force is proportional to:
The current;
The
strength of the magnetic field
The
length of wire within the magnetic field.
This
is summed up in a simple formula:
F = BIl
[B – magnetic field strength;
I
– current in A;
l
– length in m]
The
term
B
is called the
magnetic field strength,
or the flux density, and is measured
in Tesla, T. Flux density is a
vector quantity The magnetic flux
density can be thought of as the concentration of field lines.
We can increase the force by increasing any of the terms within the
equation. If we coil up the wire,
we increase its length within the magnetic field.
Worked
Example A current of 8.5 A flowing through a magnetic field is found to exert a force of 0.275 N. The length of wire in the magnetic field is 5 cm. What is the value of the magnetic field? |
Answer Formula first: F = BIl
Ţ
B = F
= ___0.275 N ___ = 0.647
T Il 8.5 A ´ 0.05 m |
In a demonstration of the above equation, the length of wire in a magnetic field is 0.05 m. When a current of 2.5 A flows, a force of 0.01 N is shown. What is the magnetic field strength? |
If the field is at any angle other than 90 degrees, the formula takes this into account with the sine function:
In a demonstration of the above equation, the length of wire in a magnetic field is 0.05 m. When a current of 2.5 A flows, a force of 0.01 N is shown. What is the magnetic field strength if the wire is at an angle of 35^{o} to the field? |
Required Practical - Force on a wire from a magnetic field
A simple experiment can be carried out to measure the force produced when a current flows through a magnetic field. The apparatus set up is straight-forward:
In the diagram, a retort rod is used. A wire in a glass tube is also effective. The horseshoe magnets are from the motor kits that most schools and colleges have.
You need to:
Measure the length of the wire that is in the magnetic field;
Find the current that produces a measurable change in the reading of the balance;
Measure the change in the reading;
Convert the reading into Newtons (as the balance will give a reading in grams);
Take at least seven readings from the minimum up to the maximum which the power supply will give;
Do repeat readings and take averages.
You then need to plot a graph which will show direct proportionality:
The magnetic field strength will come from the gradient.
Gradient = Bl
Therefore we divide the gradient by the length to get a value for the magnetic flux density.