Answer 4_10_6

A search coil has 2500 turns and an area of 1.5 10-4 m2. It is placed between the poles of a large horseshoe magnet.  It is rapidly pulled out of the field in a time of 0.30 s.  A datalogger records an average value for the emf of 0.75 V.  What is the flux density between the poles of the magnet?

 

= -N DF/Dt  (P) and DF = BDA (P)

 

0.75 = (-) 2500 B (0 - 1.5 10-4 m2) (P)

                               0.3 s

 

 

B =      0.75 V 0.3 s  (P)

       2500 1.5 10-4 m2

 

 

B = 0.6 T (P)

 

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